Example 2
Assume the following sample code: => Gate 1 => Gate 2 => Gate 3 => Gate 4
The constraints are as follows considering :
We continue with and .
The Prover calculates square matrices , and of order based on above construction:
B=\begin{bmatrix} 0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&...&0&0&0&0\ 0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&...&0&0&0&0\ .&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&...&.&.&.&.\ .&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&...&.&.&.&.\ .&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&...&.&.&.&.\ .&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&.&...&.&.&.&.\ 5&1&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&...&0&0&0&0\ 0&0&0&0&0&0&0&0&0&0&1&0&0&0&0&0&0&0&0&0&..&0&0&0&0\ 10&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&...&0&1&0&0\ 0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&0&1&...&0&0&0&0 \end{bmatrix}
C=\begin{bmatrix} 0&0&...&0&0&0&0\ 0&0&...&0&0&0&0\ .&.&...&.&.&.&.\ .&.&...&.&.&.&.\ .&.&...&.&.&.&.\ .&.&...&.&.&.&.\ 0&0&...&1&0&0&0\ 0&0&...&0&1&0&0\ 0&0&...&0&0&1&0\ 0&0&...&0&0&0&1 \end{bmatrix}
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